Calculate `E_(cell)^(@)` for the following reaction at `25^(@)C`. `A+B^(2+)(0.001 M) to A^(2+)(0.0001 M)+B` (Given. `E_(cell)=2.6805 V, 1 F=96500 C mol^(-1)`

Calculate `E_(cell)^(@)` for the following reaction at `25^(@)C`. `A+B

1.	Calculate `E_(cell)^(@)` for the following reaction at `25^(@)C`. `A+B^(2+)(0.001 M) to A^(2+)(0.0001 M)+B` (Given. `E_(cell)=2.6805 V, 1 F=96500 C mol^(-1)`
Answer» According to Nernst equation `E_(cell)=E_(cell)^(@)-(0.0591)/(n)"log"([Anode])/([Cathode])` `E_(cell)^(@)=E_(cell)+(0.0591)/(2)"log"([0.0001])/([0.001])=2.6805+0.02955" log"10^(-1)"` =2.6805-0.02955=2.6510 V

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Calculate `E_(cell)^(@)` for the following reaction at `25^(@)C`. `A+B^(2+)(0.001 M) to A^(2+)(0.0001 M)+B` (Given. `E_(cell)=2.6805 V, 1 F=96500 C mol^(-1)`

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