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Calculate energy of one mole of protons of radiation whose frequency is 5×10¹⁴ Hz. |
Answer» Energy (E) of one photon = E = hvwhere h = 6.626\xa0{tex}\\times{/tex}\xa010-34 Js.\xa0{tex}\\nu{/tex}\xa0= 5\xa0{tex}\\times{/tex}\xa01014 s-1{tex}\\therefore E = \\left( 6.626 \\times 10 ^ { - 34 } \\times 5 \\times 10 ^ { 14 } \\right){/tex}{tex}= 3.313 \\times 10 ^ { - 19 } J{/tex}Energy of 1\xa0mole\xa0of photon{tex}= \\left( 3.313 \\times 10 ^ { - 19 } J \\right) \\times \\left( 6.022 \\times 10 ^ { 23 } \\mathrm { mol } ^ { - 1 } \\right){/tex}= 1995.1\xa0kJmol-1 | |