Calculate equilibrium constant for the reaction : `Mg(s) |Mg^(2+)(0.001 M) || Cu^(2+)(0.0001 M)|Cu(s)` Given `E_((Mg^(2+)//Mg))^(@)=-2.37" V " , E_((Cu^(2+)//Cu))^(@)=0.34" V "`

Calculate equilibrium constant for the reaction : `Mg(s) |Mg^(2+)(0.00

1.	Calculate equilibrium constant for the reaction : `Mg(s) \|Mg^(2+)(0.001 M) \|\| Cu^(2+)(0.0001 M)\|Cu(s)` Given `E_((Mg^(2+)//Mg))^(@)=-2.37" V " , E_((Cu^(2+)//Cu))^(@)=0.34" V "`
Answer» Correct Answer - `4.9xx10^(90)` Step I. Calculation of emf of cell Cell reaction : `Mg(s)+Cu^(2+)(0.0001" M")toMg^(2+)(0.01" M")+Cu(s)` `E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Mg^(2+)])/([Cu^(2+)])=[0.34-(-2.37)]-(0.0591)/(2)"log"((0.001))/((0.0001))` `=2.71-0.02955" log "(10)=2.71-0.02955=2.68" V "` Step II. Calculation of equilibrium constant `logK_(C)=(nE_(cell)^(@))/(0.0591)=(2xx2.68)/(0.0591)=90.69,K_(C)="Antilog "90.69=4.9xx10^(90)`.

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Calculate equilibrium constant for the reaction : `Mg(s) |Mg^(2+)(0.001 M) || Cu^(2+)(0.0001 M)|Cu(s)` Given `E_((Mg^(2+)//Mg))^(@)=-2.37" V " , E_((Cu^(2+)//Cu))^(@)=0.34" V "`

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