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Calculate equivalent conductivity of 1 MH_(2)SO^(4) whose conductivity is 26 xx 10^(-2) "ohm"^(-1) cm^(-1) |
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Answer» 260 Concentration `= 1 MH_(2)SO_(4)=98 g//L` Eq. wt. of `H_(2)SO_(4)=49` `therefore` No. of gram equivalents per litre `=(98)/(49)=2` Equivalent conductance `=( K xx 1000)/(C)` `=(26xx10^(-2) xx 1000)/(2)` `=130 Omega^(-1) cm^(2) "mol"^(-1)` |
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