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Calculate excess pressure inside an air bubble of radius 1.0 mm and just below the surface of water. What will be the pressure inside the soap bubble? |
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Answer» Solution :GIVEN `r=1 xx 10^(-3)m` `T=0.072 Nm^(-1)` EXCESS PRESSURE `=(2T)/(r)` (because it has only the inner suface= `(2 xx 0.072)/(1 xx 10^(-3))` `=144 Nm^(-2) =0.00144 xx 10^(5)` Net pressure INSIDE the BUBBLE is `=P_(0)+(2T)/(r)=1.013 xx 10^(5)+0.00144+10^(5)` Net pressure `=1.0144 xx 10^(5)Nm^(-2)` |
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