Calculate free energy change for the following reaction at 298 K:2NO(g)+Br2(l)→2NOBr(g)Given the partial pressure of NO is 0.1 atm and the partial pressure of NOBr is 2.0 atm and ΔG0f NOBr=82.4 kJ mol−1,ΔG0NO=86.55 kJ mol−1

Calculate free energy change for the following reaction at 298 K:2NO(g

1.	Calculate free energy change for the following reaction at 298 K:2NO(g)+Br2(l)→2NOBr(g)Given the partial pressure of NO is 0.1 atm and the partial pressure of NOBr is 2.0 atm and ΔG0f NOBr=82.4 kJ mol−1,ΔG0NO=86.55 kJ mol−1
Answer» Calculate free energy change for the following reaction at $298 K$ : $2 N O (g) + B r_{2} (l) \to 2 N O B r (g)$ Given the partial pressure of $N O$ is $0.1 atm$ and the partial pressure of $N O B r$ is $2.0 a t m$ and $Δ G_{f N O B r}^{0} = 82.4 {kJ mol}^{- 1}, Δ G_{N O}^{0} = 86.55 {kJ mol}^{- 1}$