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Calculate free energy changes for expansion of 8 moles of an ideal gas from 1atm to 0.1 atm at 25 |
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Answer» Given :- P 1 =1 BAR P 2 =0.1 bar T C =273Kn=1mole; Isothermal process T=constΔU=Q+W ---- in isothermal process ΔU=0⇒Q=−WNow,W=−P 1 V 1 ln V 1 V 2 or −nRTln V 1 V 2 ⇒W= −nRT P 2 P 1 W=−1×8.314×273×ln( 0.11 )W=−8.314×273×ln10W=−5226.23 J ∴Q=5226.23 J |
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