1.

Calculate [H+] if pOH = 9.23

Answer»

pH + pOH = 14 pH = 14 – pOH = 14 – 9.23 = 4.77

pH = -log10[H+] = -4.77 = log[H+]

Taking antilog on both the sides

[H+] = antilog (-4.77) = antilog [+5 -4.77 – 5] = antilog [0.23] × 10-5 = 1.698 × 10-5] mol/dm3]



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