Calculate heat of solution of NaCl from the following data Hydration energy of Na^(+) = -389kJ mol^(-1) Hydration energy of Cl^(-) = -382kJ mol^(-1) Lattice energy of NaCl = +776 kJ mol^(-)

Calculate heat of solution of NaCl from the following data Hydration

1.	Calculate heat of solution of NaCl from the following data Hydration energy of Na^(+) = -389kJ mol^(-1) Hydration energy of Cl^(-) = -382kJ mol^(-1) Lattice energy of NaCl = +776 kJ mol^(-)
Answer» SOLUTION :Hydration ENERGY of BNaCI=Hydratin energy of `Na^(+)` hydration energy of `CI^(-)` =-389 -382 =-771 kj/mol =[-771-(-776)]=5kj/mole