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Calculate how many times more intense is 90 dB sound compared to 40 dB sound?

Answer» <html><body><p></p>Solution :Given <a href="https://interviewquestions.tuteehub.com/tag/data-25577" style="font-weight:bold;" target="_blank" title="Click to know more about DATA">DATA</a>: `L=log(I)/(I_(0))=logI-logI_(0)` <br/> We get`90 dB = 9B=logI_(1)-logI_(0)`...(1) <br/> `40dB=4B=logI_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-logI_(0)`...(2) <br/> Subtract (2) from (1) <br/> `-50dB=5B=logI_(1)-logI_(2)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>=log_(10)((I_(1))/(I_(2)))` <br/> `(I_(1))/(I_(2))=10^(5)`</body></html>


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