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Calculate how much calcium is in the amount of calcium nitrate that content 20 gram of nitrogen

Answer» One molecule of\xa0Ca(NO3)2\xa0contains 2 atoms of N.Mass of nitrogen in one mole\xa0Ca(NO3)2\xa0molecule = 28 g ( 2 x molar mass of nitrogen)28g N = one mole molecule of\xa0Ca(NO3)2.20 g N = 1x 20 /28 = 0.71 mole of\xa0Ca(NO3)2.\xa0One molecule of\xa0Ca(NO3)2\xa0contains 2 atoms of N.1 mole Ca(NO3)2 = 40 g Ca0.71 mole\xa0Ca(NO3)2\xa0= 40 x 0.71 = 28.4 g Ca.


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