Calculate (i) Mass in gram of 5.8 mol N2O (ii) Number of moles in 8.

1.	Calculate (i) Mass in gram of 5.8 mol N2O (ii) Number of moles in 8.0 g of O2 (iii) Molar mass if 11.2 L at STP weight 8.5 g
Answer» (i) Molecular mass of N₂O = 2(14) + 16 = 44 Mass = Molecular mass × No. of moles = 44 × 5.8 = 255.2 g (ii) Number of moles of O₂ = \(\frac{Mass\,of\,O_2}{Molecular\,mass\,of\,O_2}\) = \(\frac{0.8}{32}\) = 0.25 mol (iii) \(\because\) 11.2 L at STP weight = 8.5 g \(\therefore\) 22.4 L at STP will weight = \(\frac{8.5}{11.2}\) x 22.4 = 17 g mol^-1

Calculate (i) Mass in gram of 5.8 mol N2O (ii) Number of moles in 8.0 g of O2 (iii) Molar mass if 11.2 L at STP weight 8.5 g

Answer»

(i) Molecular mass of N₂O = 2(14) + 16 = 44

Mass = Molecular mass × No. of moles

= 44 × 5.8

= 255.2 g

(ii) Number of moles of

O₂ = \(\frac{Mass\,of\,O_2}{Molecular\,mass\,of\,O_2}\) = \(\frac{0.8}{32}\) = 0.25 mol

(iii) \(\because\) 11.2 L at STP weight = 8.5 g

\(\therefore\) 22.4 L at STP will weight = \(\frac{8.5}{11.2}\) x 22.4

= 17 g mol^-1