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Calculate (i) r.m.s. velocity, and (ii) mean kinetic energy of one-gram molecule of hydrogen at S.T.P. (Given, density of hydrogen at S.T.P. is 0.09 kg/ms. |
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Answer» Here, ρ = 0.09 kg/m3 P = 1.01 × 105 Pa (i) According to kinetic theory of gases, \(P=\frac{1}{3}ρc^2\) or \(c=\sqrt\frac{3P}{ρ}\) \(=\sqrt\frac{3\times1.01\times10^5}{0.09}\) = 1837.5 m/s (ii) Volume occupied by one mole of hydrogen at S.T.P. = 22.4 litres = 22.4 × 10-3m3 Mass of hydrogen, M = Volume × Density = 22.4 × 10-3 × 0.09 kg = 2.016 × 10-3 kg Mean K.E. of one-gram molecule of hydrogen at S.T.P. = 1/2 MV2 = 1/2 × 2.016 × 10-3 × (1837.5)2 = 3.4 × 103 J |
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