InterviewSolution
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InterviewSolution
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Calculate (i) rms velocity and (ii) mean kinetic energy of one gram molecule of hydrogen at STP. Given density of hydrogen at STP is `0.09 kg m^(-3)`. |
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Answer» Here `rho = 0.09 kg m^(-3)` At STP, pressure `P= 0.01 xx 10^(5)Pa`. According to kinetic theory of gases. `P = 1/3 rho C^(2)` or `C= sqrt((3P)/(rho)) = sqrt((3xx 1.01 xx 10^(5))/(0.09)) = 1837.5 ms^(-1)` Volume occupied by one mole of hydrogen at `STP = 22.4 "litres" = 22.4 xx 10^(-3)m^(3)` `:.` Mass of hydrogen `M =` volume `xx` density = ` 22.4 xx 10^(-3) xx 0.09 = 2.016 xx 10^(-3)kg` Average `K.E//mole = 1.2 MC^(2)` `=1/2 xx (2.016 xx 10^(-3)) xx (1837.5)^(2) = 3403.4 J`. |
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