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Calculate Karl Pearson's coefficient of correlation between the values of X and Y for the following data: Assume 69 and 112 as the mean values for X and Y respectively. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/TRJ_ECO_XI_C12_S01_019_S01.png" width="80%"/> <br/> `r=(sumdxdy-((sumdx) xx(sumdy))/(N))/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(sumdx^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=((sumdx)^(2))/(N))xx sqrt(sumdy^(2)-((sumdy)^(2))/(N)))` <br/> `=(2,116-((<a href="https://interviewquestions.tuteehub.com/tag/47-317855" style="font-weight:bold;" target="_blank" title="Click to know more about 47">47</a>)xx(108))/(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>))/(sqrt(1,475-((47)^(2))/(8))xxsqrt(3,468-((108)^(2))/(8)))`<br/> `=(2,116-634.5)/(sqrt(1,475-276.125)xxsqrt(3,468-1,458))=(1,481.5)/(sqrt(1,198.875)xxsqrt(2,010))=(1,481.5)/(34.62xx44.83)=(1,481.5)/(1,552.0146)=0.955` <br/> Coefficient of Correlation (r)=0.955</body></html> | |