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Calculate Karl Pearson's coefficient of correlation between the values of X and Y for the following data: Assume 69 and 112 as the mean values for X and Y respectively. |
Answer» SOLUTION : `r=(sumdxdy-((sumdx) xx(sumdy))/(N))/(SQRT(sumdx^(2)=((sumdx)^(2))/(N))xx sqrt(sumdy^(2)-((sumdy)^(2))/(N)))` `=(2,116-((47)xx(108))/(8))/(sqrt(1,475-((47)^(2))/(8))xxsqrt(3,468-((108)^(2))/(8)))` `=(2,116-634.5)/(sqrt(1,475-276.125)xxsqrt(3,468-1,458))=(1,481.5)/(sqrt(1,198.875)xxsqrt(2,010))=(1,481.5)/(34.62xx44.83)=(1,481.5)/(1,552.0146)=0.955` Coefficient of Correlation (r)=0.955 |
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