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Calculate KB for water latent heat of vaporization for water is 540 cal per gram |
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Answer» Solution verified Verified by Toppr Correct OPTION is A 26 cal.K −1 mol −1
Solution:- (A) 26cal/mol−K As we KNOW that, ΔS= T ΔH
ΔH=540cal/g Mol. wt. of water =18g ΔH (PER mole) =ΔH (per gm) ×Mol. wt. ΔH (per mole) =540×18=9720cal/mol Now, as we know that, ΔS= T ΔH
GIVEN T=100℃=(273+100)=373K ∴ΔS= 373 9720 =26cal/(mol.K) PLEASE MARK ME AS BRAINLISTS |
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