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Calculate magnitude of DeltaH in calorie for 1 mol of an ideal gas undergoingadiabatic reversible process from 8 atm, 300 K to 2 atm.(Given : gamma=2, R=2Cal//K//mol) |
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Answer» <P> SOLUTION :[0600]`(T_(2))/(T_(1))=((P_(1))/(P_(2)))^((1-GAMMA)/(gamma))=((8)/(2))^((1-2)/(2))=((4)/(1))^((-1)/(2))=((4)/(1))^((1)/(2))=(1)/(2)` `T_(2)=150K` `DeltaH=1xx(gammaR)/(gamma-1)(-150)=(2xx2)/(1)xx(-150)=-600` |
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