1.

Calculate magnitude of DeltaH in calorie for 1 mol of an ideal gas undergoingadiabatic reversible process from 8 atm, 300 K to 2 atm.(Given : gamma=2, R=2Cal//K//mol)

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SOLUTION :[0600]
`(T_(2))/(T_(1))=((P_(1))/(P_(2)))^((1-GAMMA)/(gamma))=((8)/(2))^((1-2)/(2))=((4)/(1))^((-1)/(2))=((4)/(1))^((1)/(2))=(1)/(2)`
`T_(2)=150K`
`DeltaH=1xx(gammaR)/(gamma-1)(-150)=(2xx2)/(1)xx(-150)=-600`


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