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Calculate mass of water present in `499gm CuSO_(4).5H_(2)O` ? (Atomic mass `-Cu = 63.5, S = 32,O = 16, H =1)` . |
Answer» Molar mas of `CuSO_(4).5H_(2)O = 249.5` moles of `CuSO_(4).5H_(2)O = (499)/(249.5) = 2` Each mole `CuSO_(4).5H_(2)O` has `5mol H_(2)O` `2` mole `CuSO_(4).5H_(2)O` has `10 mol H_(2)O` Mass of `10mol H_(2)O = 10 xx 18 = 180 gm` . |
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