1.

Calculate mass of water present in `499gm CuSO_(4).5H_(2)O` ? (Atomic mass `-Cu = 63.5, S = 32,O = 16, H =1)` .

Answer» Molar mas of `CuSO_(4).5H_(2)O = 249.5`
moles of `CuSO_(4).5H_(2)O = (499)/(249.5) = 2`
Each mole `CuSO_(4).5H_(2)O` has `5mol H_(2)O`
`2` mole `CuSO_(4).5H_(2)O` has `10 mol H_(2)O`
Mass of `10mol H_(2)O = 10 xx 18 = 180 gm` .


Discussion

No Comment Found

Related InterviewSolutions