Calculate molality of sulphuric acid solution in which mole fraction o

1.	Calculate molality of sulphuric acid solution in which mole fraction of water is 0.85
Answer» If the mole fraction of water is 0.85, the mole fraction of sulfuric acid is 0.15.So, we can express the concentration as{tex}\\frac { 0.15 \\mathrm { mol } \\text { sulfuric acid } } { 0.85 \\text { mol water } }{/tex}Convert moles of water to kilograms of waterMass of water =\xa0{tex}0.85 \\mathrm { mol } \\mathrm { H } _ { 2 } \\mathrm { O } \\times \\frac { 18.02 \\mathrm { g } \\mathrm { H } _ { 2 } \\mathrm { O } } { 1 \\mathrm { mol } \\mathrm { H } _ { 2 } \\mathrm { O } } \\times \\frac { 1 \\mathrm { kg } \\mathrm { H } _ { 2 } \\mathrm { O } } { 1000 \\mathrm { g } \\mathrm { H } _ { 2 } \\mathrm { O } }{/tex}=0.0153 kg H2OCalculate the molal concentration of the waterm =\xa0{tex}\\frac { 0.15 \\mathrm { mol } \\text { sulphuric acid } } { 0.0153 \\mathrm { kg } \\text { water } }{/tex}= 9.8 mol/kg

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