Calculate molar conductance for `NH_(4)OH`, given that molar conductance for `Ba(OH)_(2), BaCI_(2)` and `NH_(4)CI` are `523.28, 280.0` and `129.8 ohm^(-1) cm^(2) mol^(-1)` respectively.

Calculate molar conductance for `NH_(4)OH`, given that molar conductan

1.	Calculate molar conductance for `NH_(4)OH`, given that molar conductance for `Ba(OH)_(2), BaCI_(2)` and `NH_(4)CI` are `523.28, 280.0` and `129.8 ohm^(-1) cm^(2) mol^(-1)` respectively.
Answer» `mu_(Ba(OH)_(2))^(prop) = lambda_(Ba^(2+))^(prop) +2lambda_(OH^(-))^(prop) = 523.28` ...(i) `mu_(BaCI_(2))^(prop) = lambda_(Ba^(2+))^(prop) +2lambda_(CI^(-))^(prop) = 280.00` ...(ii) `mu_(NH_(4)CI)^(prop) = lambda_(NH_(4)^(+))^(prop) +lambda_(CI^(-))^(prop) = 129.80` ...(iii) `mu_(NH_(4)OH)^(prop) = lambda_(NH_(4)^(+))^(prop) +lambda_(OH^(-))^(prop) = ?` Eq.(iii) `+(Eq(i))/(2) -(Eq.(ii))/(2)` will gives `lambda_(NH_(4)^(+))^(prop) +lambda_(OH^(-))^(prop) = lambda_(NH_(4)OH)^(prop) = (502.88)/(2) = 251.44 ohm^(-1) cm^(2) mol^(-1)`

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Calculate molar conductance for `NH_(4)OH`, given that molar conductance for `Ba(OH)_(2), BaCI_(2)` and `NH_(4)CI` are `523.28, 280.0` and `129.8 ohm^(-1) cm^(2) mol^(-1)` respectively.

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