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Calculate mole fraction of HCI in a solution containing 24.8% of HCI by mass. |
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Answer» Correct Answer - Mole fraction HCI= 0.1398 Given : % by weight of HCI = 24.8 , Mole fraction of HCI= `X_(HCI)= ?` Consider 100 gram HCI solution . `:.` Weight of a solute (HCI) =24.8 g Weight of a solvent (water) = 100 -24.8 = 75.2 g `:. ` Moles of solvent = `n_(H_(2)O) = .(W_(H_(2)O))/(M_(H_(2)O))=(75.2)/(18) =4.178 mol H_(2)O` Moles of solute `=n_(H_(2)O) =(W_(H_(2)O))/(36.5) =(24.8)/(36.5)=0.6795 mol` `:. ` Total moles in solution `= n_(H_(2)O) + n_(HCI)` `=4. 178 + 0.6795 =4. 8575` Mole fraction of HCI `X_("HCI") =("moles of HCI")/("total moles in solution")` `= (0.6795)/(4.8575)= 0.1398` |
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