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Calculate mole fraction of solute in its 2 molal aqueous solution . |
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Answer» Correct Answer - Mole fraction of the solute = 0.0347 Given : Concentration of solution =2 molal = 2 m Hence 2 moles of a solute are present in 1000 grams water . `:. W_(H_(2)O) =100 g` `:.` Number of moles of water `=n_(H_(2)O) =(W_(H_(2)O))/(M_(H_(2)O))` `= (1000)/(18)` `=55.56 `mol `:. ` Total moles in solution `=n_(H_(2)O) + n_(solute)` `=55.56 +2` ` = 57 .56 `mol `:. ` Mole fraction of a solute `=("Number of moles of solute" )/("Total moles in solution ")` `:. X_("solute") =(2)/(56.56) = 0.0347` |
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