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Calculate normality of Na which contain 3g NaOH in 250 ml water |
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Answer» Hope it will help you EXPLANATION:MOLAR mass of NaOH = 23+16+1 = 40g/mol1mg = 1×10^-3g250ml = 25×10¹×10^-3 L = 25×10^-2LMolarity : the number of moles of solute present in a one liter VOLUME of a solution .Molarity = number of moles/volume of solutionMolarity = mass of solute/(molar mass of solute×volume of solution)Molarity = 10^-3/(40×25×10^-2)Molarity = 10^-3+2/1000Molarity = 10^-1/10^3Molarity = 10^-1–3Molarity = 10^-4mol/L |
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