Calculate [OH^(-)] if pH = 5.284.

1.	Calculate [OH^(-)] if pH = 5.284.
Answer» Solution :`pH=-log_(10)[H^(+)],[H^(+)]="ANTI"LOG[-5.284]="anti"log[6-5.284-6]` `[H^(+)]="anti"log(0.716-6)="anti"log[0.716]xx10^(-6)=5.2xx10^(-6)mol//dm^(3)` `[H^(+)][OH^(-)]=10^(-14),SO[OH^(-)]=10^(-14)/([H^(+)])=10^(-14)/(5.2xx10^(-6))=0.192xx10^(-8)mol//dm^(3)`

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