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| 1. |
Calculate pH for 0.001M NaOH |
| Answer» NaOH is a strong base that dissociates completely\xa0Therefore [OH-] = [NaOH] = 0.001M\xa0First calculate the pOH of the solution :\xa0pOH = -log [OH-]\xa0pOH = -log 0.001\xa0pOH = 3.00\xa0pH = 14.00 - pOH\xa0pH = 14.00 - 3.00\xa0pH = 11.00 | |