InterviewSolution
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InterviewSolution
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Calculate pH for: (a) `0.01N Ca(OH)_(2)` (b) `0.01M Ca(OH)_(2)` (c ) `0.0008M Mg(OH)_(2)` Assume complete ionisation of each. |
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Answer» (a) `0.01N Ca(OH)_(2):` `{:(Ca(OH)_(2),rarrCa^(2+)+,2OH^(-)),(10^(-2)N,0,0),(0,10^(-2),10^(2-)):}` Eq. ratio of `Ca(OH)_(2): Ca^(2+):OH^(-1)::1:1:1` `(.: "Equivalent litre"^(-1)"are given")` `:. [OH^(-)]=10^(-2)M` `:. pOH=2` `:. pH=12` (b) `0.01M Ca(OH)_(2)`: `{:(Ca(OH)_(2)rarr,Ca^(2+)+,2OH^(-)),(10^(-2)M,0,0),(0,10^(-2),2xx10^(-2)):}` Mole ratio of `Ca(OH)_(2):Ca^(2+):OH^(-1):1:1:2` `:. [OH^(-)]=2xx10^(-2)M` `:. pOH=1.6989` `:. pH=14-1.6989=12.3011` (c ) `0.0008M Mg(OH)_(2):` `{:(Mg(OH)_(2)rarr,Mg^(2+)+,2OH^(-)),(8xx10^(-4)M,0,0),(0,8xx10^(-4),2xx8xx10^(-4)):}` `:.[OH^(-)]=16xx10^(-4)M` `:. pOH=2.7958` `:. pH=11.2042` |
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