1.

Calculate pH of 0.005 M H2SO4.

Answer»

pH = -log10[H+

= -log10[0.005 × 2] 

= -log10[0.01] 

= -log10[1 × 10-2pH 

= 2 – log10 

= 2 – 0 

= 2



Discussion

No Comment Found

Related InterviewSolutions