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Calculate relative rate of effusion of `O_(2)` to `CH_(4)` through a container containing `O_(2)` and `CH_(4)` in 3:2 mass ratio:A. `(3sqrt(2))/(4)`B. `(3sqrt(2))/(8)`C. `(3)/(2sqrt(2))`D. `(3sqrt(2))/(2)` |
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Answer» `(r_(o_(2)))/(r_(CH_(4)))=(n_(o_(2)))/(n_(CH_(4)))=sqrt((M_(CH_(4)))/(M_(O_(2))))` `=(3)/((2)/(2))=sqrt((16)/(32))` `=(3)/(4sqrt(2))` |
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