Calculate standard entropy change in the reaction Fe_(2)O_(3(s)) + 3H_(2(g)) rarr 2Fe_((s)) + 3H_(2)O_((l)) Given: S_(m)^(0) (Fe_(2)O_(3), s) = 87.4 S_(m)^(0) (Fe, s) = 27.3, S_(m)^(0) (H_(2)g) = 130.7, S_(m)^(0) (H_(2)O, 1) = 69.9 JK^(-1) mol^(-1)

Calculate standard entropy change in the reaction Fe_(2)O_(3(s)) + 3H_

1.	Calculate standard entropy change in the reaction Fe_(2)O_(3(s)) + 3H_(2(g)) rarr 2Fe_((s)) + 3H_(2)O_((l)) Given: S_(m)^(0) (Fe_(2)O_(3), s) = 87.4 S_(m)^(0) (Fe, s) = 27.3, S_(m)^(0) (H_(2)g) = 130.7, S_(m)^(0) (H_(2)O, 1) = 69.9 JK^(-1) mol^(-1)
Answer» `-212.5 JK^(-1)` `-215.2 JK^(-1) mol^(-1)` `-120.9 JK^(-1)` none of these Solution :`Delta S^(0) = S_(P^(0) - S_(R )^(0)` `= 2 xx S_(Fe)^(0) + 3S_(H_(2)O)^(0) - S_(Fe_(2)O_(3))^(0) - 3S_(H_(2))^(0)` `= 2 xx 27.3 + 3 xx 69.9 - 87.4 - 3 xx 130.7` `= -215.2 J//K`