1.

Calculate standard free energy change for the reaction `2Ag+2H^(+)rarrH_(2)+2Ag^(+)` Given : `E_(Ag^(+)//Ag)^(@)=+0.80V`A. 308.08 kJB. 154.4 kJC. 77.2 kJD. `-154.4` kJ

Answer» Correct Answer - B
`E_(cell)^(@)+E_(H_(2))^(@)-E_(Ag)^(@)`
= 0-0.80 = 0.80
`DeltaG^(@)= -nFE_(cell)^(@)` = `-2xx96500xx(-1.80)`
=+154.4kJ


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