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Calculate standard free energy change for the reaction `2Ag+2H^(+)rarrH_(2)+2Ag^(+)` Given : `E_(Ag^(+)//Ag)^(@)=+0.80V`A. 308.08 kJB. 154.4 kJC. 77.2 kJD. `-154.4` kJ |
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Answer» Correct Answer - B `E_(cell)^(@)+E_(H_(2))^(@)-E_(Ag)^(@)` = 0-0.80 = 0.80 `DeltaG^(@)= -nFE_(cell)^(@)` = `-2xx96500xx(-1.80)` =+154.4kJ |
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