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Calculate Standard Gibbs Free Energy forthe given reaction : Zn + Cu2+ → Zn2+ + Cu.Given E⁰cell = 1.10V |
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Answer» Answer: Explanation: ∆G° = -N*F*E° CELL. (F=96500 Cmol^-1)
= -2*96500*1.10 = -2.213 KJ |
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