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Calculate sum of maximum & minimum number of electrons present in Mn having `n + l ge 4, |m| = 1, s = + 1//2`

Answer» Correct Answer - 9
`(Deltax)=(Deltalambda)`
`Deltax xx (h)/(lambda^(2))Deltalambda=(h)/(4pi)`
`Deltalambda=(lambda^(2))/(4pi)=(lambda)/(2sqrt(pi))=(18sqrt(pi))/(2sqrt(pi))Å=9Å`


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