Calculate tge kinetic energy of 3 moles of carbondioxide at 27 degree

1.	Calculate tge kinetic energy of 3 moles of carbondioxide at 27 degree
Answer» ANSWER: KINETIC energy = 3nRT/2 =3 x 3 x 8.314 x (273+27)/2 =9 x 8.314 x 300 / 2 =22447.8 / 2 = 11223.9 Joules.

Answer»

KINETIC energy = 3nRT/2

=3 x 3 x 8.314 x (273+27)/2

=9 x 8.314 x 300 / 2

=22447.8 / 2

= 11223.9 Joules.

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