Saved Bookmarks
| 1. |
Calculate the amound of benzoic acid `(C_(6)H_(5)COOH)` required for preparing `250mL` of `0.15 M` solution in methanol. |
|
Answer» Correct Answer - `4.575g` Molecular mass of `(C_(6)H_(5)COOH)` `=12xx6+5+12+32+1=122g mol^(-1)` mmoles of benzoic aci`=MxxV` ltbr. `=250xx0.15=37.5` `=37.5xx10^(-3)mol` Amount of benzoic acid `=` Moles `xx Mw_(2)` ltbr. `=37.5xx10^(-3)xx122` `=4.575g` |
|