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Calculate the amount of 50% `H_(2)SO_(4)` required to decompose 25g calcium carbonate :-A. 98gmB. 49gmC. 24.5gmD. 196gm |
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Answer» Correct Answer - B `{:(CaCO_(3)+,H_(2)SO_(4),to,CaSo_(4),+H_(2)O+CO_(2),),(100g,98g,,,,):}` `100g CaCO_(3) require 98 gm H_(2)SO_(4)` ` 25 g CaCO _(3)require (98)/(100)xx25 gm pure H_(2) SO_(4)` ` = 24.5g pure H_(2)SO_(4)` Hence, wt 50% pure `H_(2)SO_(4)` will be 49.5 gm |
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