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Calculate the amount of calcuium oxide required when it reacts with `852 g` of `P_(4) O_(10)`. |
Answer» Correct Answer - A `6CaO + P_(4) O_(10) rarr 2Ca_(3) (PO_(4))_(2)` `6CaO -= P_(4)O_(10)` `(6 (40 + 16))/(W) = ((31 xx 4) + (16 xx 10))/(852)` or `W = 1008 g` |
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