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() Calculate the amount of CO, formed by the complete combustion of 80g of methane as per the reactiorCH4 + 202 → CO2 + 2H2O(ii) Define 1 mole. |
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Answer» CH4(16g) + 2O2 (64g) = CO2 (44g) + 2H2O(36g) 1 mole 2 mole 1 mole 2 mole amt of CO2 required for complete combustion of 1 mole ofCH4 = 44gamount of CO2 required for complete combution of 80 g of CH4 = ( 80/16 ) * 44g = 5*44 = 220 g |
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