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Calculate the amount of glucose present in 500 ml of m/2 glucose solution |
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Answer» Answer: 6
H 12
O 6
contains 6.02×10 molecules 6
H 12
O 6
contains 6.02×10 23 molecules ∴ No. of moles having 6.02×10 22 molecules= 6.02×10 23
6.02×10 22
=0.1 moles Now, Molarity= VinL No.ofmoles
= 0.5L 0.1mol
=0.2M |
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