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calculate the amount of heat envolve when 200cm3 of 0.2m HCL solution is mixed with 300cm3 of 0.1m NaOH solution​

Answer»

tion:Answer500 CM 500 cm 3500 cm 3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions.500 cm 3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions.200 cm 500 cm 3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions.200 cm 3500 cm 3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions.200 cm 3 of 0.2 M NAOH corresponds to 0.2×0.2=0.04 moles of HYDROXIDE ions.500 cm 3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions.200 cm 3 of 0.2 M NaOH corresponds to 0.2×0.2=0.04 moles of hydroxide ions.sodium hydroxide is completely neutralize by Hcl500 cm 3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions.200 cm 3 of 0.2 M NaOH corresponds to 0.2×0.2=0.04 moles of hydroxide ions.sodium hydroxide is completely neutralize by HCLTHE enthalpy of neutralisation is 57.3 kJ/mol. For 0.04 moles, the enthalpy of neutralisation is 0.04×57.3=2.292 kJ



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