Calculate the amount of heat necessary to raise 180 g of water from 25^@C to 100^@C . Molar heat capacity of water is 75.3 "J mol"^(-1) K^(-1)

Calculate the amount of heat necessary to raise 180 g of water from 25

1.	Calculate the amount of heat necessary to raise 180 g of water from 25^@C to 100^@C . Molar heat capacity of water is 75.3 "J mol"^(-1) K^(-1)
Answer» Solution :Given : Number of moles of water `n=(180 G)/(18 g "mol"^(-1))=10` mol molar heat capacity of water `C_P=75.3 J K^(-1) "mol"^(-1)` `T_2=100^@C`=373 K `T_1=25^@C` =298 K `DeltaH`=? `DeltaH=nC_P (T_2-T_1)` `DeltaH="10 mol" xx "75.3 J mol"^(-1) K ^(-1) xx(373-298)K` `DeltaH`=56475 J `DeltaH` =56.475 kJ