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    				| 1. | Calculate the amount of ice that will separate out on cooling containing `50 g `of ethylene glycol in `200 g` of water to `-9.3^(@)C (K_(f)` for water =`1.86 K mol^(-1) kg`) | 
| Answer» Given `DeltaT = 9.3, w = 50 g`, `K_(f)` for `H_(2)O = 1.86 K mol^(-1) kg, m_("glycol") = 62` `because Delta T = (1000 K_(f) xx w)/( m xx W)` `:. 9.3 = (1000 xx 1.86 xx 50)/(62 xx W)` `:. W_("water") = 161. 29 g` Thus, weight of ice seprated `= 200-161.29` `= 38.71 g` | |