Calculate the amount of NaOH present in 200 mL of 0.5 N solution.

1.	Calculate the amount of NaOH present in 200 mL of 0.5 N solution.
Answer» SOLUTION :Normality of solution (N) `= ("Mass of NAOH")/("EQUIVALENT mass of NaOH"/("Volume of solution in mL"/1000))` `("0.5 equiv L"^(-1))=(W)/(("40 g equiv"^(-1))xx("0.2 L"))` `W=("0.5 equiv L"^(-1))xx("40 g equiv"^(-1))xx("0.2 L")=4g`.

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