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Calculate the amount of water (g) produced by the combustion of 16 g of methane. |
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Answer» CH4(g) + 2O2(g) → CO2(g) + 2H2O(1) 1 mole = 16 g of CH4 gives 2 moles of H2O i.e., 2 × 18 = 36 g of H2O. |
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