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Calculate the amount of water produced by the combustion of 32 g of methane. |
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Answer» Solution :`CH_(4(G))+2O_(2(g))rarrCO_(2(g))+2H_(2)O_((g)) ` As per the stoichiometric EQUATION, Combustion of 1 MOLE (16 g) `CH_(4)` produces 2 moles (2 `xx `18 = 36 g) of water.  Combustion of 32 g `CH_(4)` produces `(36 g H_(2)O)/(16g CH_(4)) xx 32xxCH_(4)` 2= 72 gof water |
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