Calculate the amount of work done in rotating a dipole, of dipole moment 5 x 10-8cm, from its position of stable equilibrium to the position of unstable equilibrium, in electric field of intensity 104N/C.

Calculate the amount of work done in rotating a dipole, of dipole mome

1.	Calculate the amount of work done in rotating a dipole, of dipole moment 5 x 10-8cm, from its position of stable equilibrium to the position of unstable equilibrium, in electric field of intensity 104N/C.
Answer» Dipole moment P =5 x10^-4Cm. Electric field (E) =10⁴N/C At stable equilibrium θ₁ = 0° At unstable equilibrium θ₂ =180° Work done = - PE (cosθ₂ - cosθ₁) = -(5 x 10^-8 ) (10⁴ ) (cos180 - cos0) =10 x10^-4J

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Calculate the amount of work done in rotating a dipole, of dipole moment 5 x 10-8cm, from its position of stable equilibrium to the position of unstable equilibrium, in electric field of intensity 104N/C.

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