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Calculate the amount of work done in rotating a dipole, of dipole moment 3 x 10-8cm, from its position of stable equilibrium to the position of unstable equilibrium, in a uniform electric field of intensity 104N/C. |
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Answer» P = 3 x 10-8cm ; E =104N/C At stable equilibrium (θ1 ) = 0° At unstable equilibrium (θ2) =180° Work done in rotating dipole is given by: W = PE (cosθ1 - cosθ2 ) = (3 x 10-8) (104) [cos0º - cos180º] = 3 x10-4 [1 - (- 1)] W = 6 x 10-8J |
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