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Calculate the amount of work done is blowing a soap bubble to a radius of 0.05m by blowing the soap solution which has a surface tension of 0.03Nm^(-2). |
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Answer» Solution :Given `T=0.30Nm^(-1)` `r=0.05m` We know that W=(T) (surface area) SINCE soap bubble has two free surfaces `SA=2(4pir^(2))=8pir^(2)` Hence `W=T(8pir^(2))` i.e, `W=0.3 xx 8 xx 3.142 xx (0.05)^(2)` i.e, `W=1.88 xx 10^(-3)J` |
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