Calculate the angle for which a cyclist bends when he turns a circular path of length 34.3 m in sqrt(22) s.

Calculate the angle for which a cyclist bends when he turns a circular

1.	Calculate the angle for which a cyclist bends when he turns a circular path of length 34.3 m in sqrt(22) s.
Answer» Solution :Given Data: `l= 34.3 m, t= SQRT(22), g = 9.8 MS^(-2), THETA = ?` If r is radius of CIRCULAR path, then length of path = `2pir = 34.3` m `r =(34.3)/(2pi)` m. and time taken t = `sqrt(22)` s As tan `theta = (v^(2))/(rg)` `:. tan theta = ((34.3)/(sqrt(22)))^(2) xx (2pi)/(34.3 xx 9.8)` tan `theta = (34.3xx34.3)/(22) xx (2xx22)/(7xx343xx9.8) = (34.3xx2)/(68.6) = 1`[`:. theta = 45^(@)`]