1.

Calculate the angle of (a) 1^(@) (degree) (b) 1' (minute of arc or arcmin) and ("c") 1" (second of arc or arc second ) in radians. Use 360^(@) = 2pi rad, 1^(@)=60' and 1'=60".

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a)We know that, <br/> `<a href="https://interviewquestions.tuteehub.com/tag/180-279527" style="font-weight:bold;" target="_blank" title="Click to know more about 180">180</a>^(@)= <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>` rad <br/> then `1^(@)=(?)` <br/> `:.1^(@)=(pi)/(180)=(3.412)/(180)` <br/>`:.1^(@)=0.01745` <br/> `:.1^(@)~~1.745xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` rad <br/> (b) We know that, <br/> `60.(min)=1^(@)` <br/> and `1^(@)=1.745xx10^(-2)` rad <br/> `:.60.=1.745xx10^(-2)` rad <br/> `:. 60.=1.745xx10^(-2)` and <br/> then `1.=(?)` <br/> `1=(1.745xx10^(-2))/(60)=0.02908xx10^(-2)` <br/> `:.1=2.91xx10^(-4)` rad <br/> We know that, <br/> `60..(sec)=1.(min)` <br/> `and 1.(min)=2.908xx10^(-4)` rad <br/> `:. 60..=2.908xx10^(-4)` rad <br/> then `1,,=(?)` <br/> `I..=(2.908xx10^(-4))/(60)=0.048466xx10^(-4)` <br/> `:.1..~~4.85xx10^(-6)` rad</body></html>


Discussion

No Comment Found