1.

Calculate the angular momentum and rotational kinetic energy of the earth about its own axis. Given mass of the earth is 6 xx 10^(24)kg and its radius = 6.4 xx 10^3 km. [Moment of inertia of the earth about its axis of rotation is 2/5 mr^(2)]

Answer»

Solution :`T =24h, L = (2//5) mr^(2) xx(2pi//T) = 7.14 xx 10^(23)Js, K.E. (1//2) Iomega^(2) = (1//2)L omega = (pi)(L//T) = 2.6 xx 10^(29)` J


Discussion

No Comment Found